16x^2+33x-16=0

Solution for 16x^2+33x-16=0 equation:

16x^2+33x-16=0

a = 16; b = 33; c = -16;
Δ = b2-4ac
Δ = 332-4·16·(-16)
Δ = 2113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{2113}}{2*16}=\frac{-33-\sqrt{2113}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{2113}}{2*16}=\frac{-33+\sqrt{2113}}{32}
$